| M4 | Lesson #3 | Orders of reactions |
Topics
Introduction of rate laws
Orders of reactions
Determining rate experimentally
a) Graphical method
b) Method of initial rates
Reaction mechanisms
Exponents and Orders of reactions
The values of exponents (m or n) can only be determined through experimentation and may or may not be the values of the coefficients in the balanced chemical equation. The exponent values are usually 0, 1 or 2 but may be 3 or in some cases even fractions. In our discussion we will look at values of only 0, 1 or 2. The following points can be made about the exponents and orders of the reactions.
| Reaction #1 |
2 N2O5 (g)
|
|
4 NO2 (g)
|
+
|
5 O2 (g)
|
Experimentally the rate was found to be first order for N2O5 (g). That is the rate varies directly with the [N2O5 (g)]. Therefore the following rate law can be written.
Rate = k [N2O5 (g)] 1
Note:
- The value of exponent is not the same as the balance for N2O5 in the equation.
- The overall reaction order would be first order.
Reaction #2 NO2 (g) + CO (g) NO (g) + CO2 (g)Experimentally the rate was found to be second order for NO2 (g) and zero order for CO (g). Therefore the following rate law can be written.
Rate = k [NO2] 2 [CO] 0
Note:
- The value of the exponent for [NO2] and [CO] is not the same as the balanced equations.
- The overall reaction order is second order ( 2 + 0 ).
Reaction #3 2 HI (g) H2 (g) + I2 (g)Experimentally the rate was found to be second order for HI (g). The following rate law is written.
Rate = k [HI] 2
Note:
- The value of the exponent for HI is the same as the coefficient in the balanced equation.
- The overall reaction order is second order.